Prove that 1/(2+3^1/2)Is an irrational number
Answers
Answer:
CASE I -
Let us assume that √3 is a rational number.
Then, as we know a rational number should be in the form of p/q
where p and q are co- prime number.
So,
√3 = p/q { where p and q are co- prime}
√3q = p
Now, by squaring both the side
we get,
(√3q)² = p²
3q² = p² ........ ( i )
So,
if 3 is the factor of p²
then, 3 is also a factor of p ..... ( ii )
=> Let p = 3m { where m is any integer }
squaring both sides
p² = (3m)²
p² = 9m²
putting the value of p² in equation ( i )
3q² = p²
3q² = 9m²
q² = 3m²
So,
if 3 is factor of q²
then, 3 is also factor of q
Since
3 is factor of p & q both
So, our assumption that p & q are co- prime is wrong
Hence,. √3 is an irrational number
CASE II -
Let 1/2+√3 be a rational number.
A rational number can be written in the form of p/q where p,q are integers.
1/(2+√3) = p/q
√3 = p/q - 1/2
√3 = (2p-q)/2q
p, q are integers then (2p-q)/2q is a rational number.
Then √3 is also a rational number.
But this contradicts the fact that √3 is an irrational number.
So,our supposition is false.
Therefore,1/(2+√3) is an irrational number