Prove that (1/√2+√3) + (2/√5-√3)+( 1/√5-√2)=0
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Answer:
Step-by-step explanation:
1/(sqr(2)+sqr(3))=sqrt(3)-sqrt(2)/1=sqrt(3)-sqrt(2)
2/(sqrt(5)-sqrt(3)=2*(sqrt(5)+sqrt(3))/2=sqrt(5)+sqrt(3)
1/(sqrt(5)-sqrt(2))=sqrt(5)+sqrt(2)/3
sqrt(3)-sqrt(2)+sqrt(5)+sqrt(3)+(sqrt(5)+sqrt(2)/3)
=3sqrt(3)-3sqrt(2)+3sqrt(5)+3sqrt(3)+sqrt(5)+sqrt(2)/3
=6sqrrt(3)-2sqrt(2)+4sqrt(5)/3
As per the auestion the LHS is not equal to zero
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