Question

Prove that 1=2. first person who answers will be marked as brainlist

Answer 1

Hey mate,....

I will try to prove this using calculus:

Assume a non-zero variable x

Now, we know that

x=x

> Then..

x+x=2x

x+x+x=3x

> Repeating x times...

x+x+x+......(x times)=x²

> Differentiating LHS and RHS with respect to x:

d(x+x+x+……)/dx=d(x²)/dx

1+1+1+1....(x times)=2x

x=2x

> Cancelling out the variable x from both sides:

1=2

Hence Proved.

Hope it will help you.

✨ It's M.S.V.

Answer 2

$\mathfrak{\huge{\underline{Solution:}}}$


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$\: \: \: \: \: \: \: \: \sf1 = 1 \\ \sf 1 - 1 = 1 {}^{2} - {1}^{2} \: \: \: \: \: \: \: \: \: \{ a {}^{2} - b {}^{2} = (a - b)(a + b) \} \\ \sf1 - 1 =(1 - 1)(1+ 1) \\ \\ \sf Dividing \: (1 - 1) \: on \: both \: side \\ \\ \sf\frac{ \cancel{(1 - 1)}}{ \cancel{(1 - 1)}} = \frac{ \cancel{(1 - 1)}(1 + 1)}{ \cancel{(1 - 1)}} \\ \\ \huge{\boxed{ \sf \blue{1 = 2}}} \\ \\ \sf \large {Hence \: Proved!!!}$

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