Question

Prove that 1/√2 is irrational.​

Answer 1

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Answer 2

$let \: \frac{1}{ \sqrt{2} } \: be \: a \: rational \: no. \\ so \: \frac{1}{ \sqrt{2} } = \frac{a}{b} \\ → \sqrt{2} a = b \\ → \sqrt{2} = \frac{b}{a} \\ → \sqrt{2} \: not = \frac{b}{a} \\ as \: \sqrt{2} \: is \: irrational \: and \: \frac{b}{a} \: is \: rational.$

$which \:condradict \: our \: sopposition \: tha \: \frac{1}{ \sqrt{2} } is \: rational$

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