prove that 1/2+sq. root of 3 + 2/sq root of 5 - sq. root of 3 +1/2- square root of 5 = 0
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Answer:
the given equation is 1\2+root3+2\root5-root3+1\2-root5
Step-by-step explanation:
After rationalising the above equation, we get
=2-root3\4-3+2root5+2root3\5-3+2+root 5\4-5
=2-root3+root5+root3-2-root5
=0
HENCE PROVED
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