Question

Prove that 1=2 using a&b method​

Answer 1

Answer:

$\huge\mathfrak\pink{sᴏʟᴜᴛɪᴏɴ:- }$

Here's how it works:

$\red\longrightarrow$ Assume that we have two variables a and b, and that: a = b.

$\red\longrightarrow$ Multiply both sides by a to get: a$^2$ = ab.

$\red\longrightarrow$ Subtract b$^2$ from both sides to get: a$^2$ - b$^2$ = ab - b$^2$

$\red\longrightarrow$ (a + b)(a - b) = b(a - b)

$\red\longrightarrow$ Since (a - b) appears on both sides, we can cancel it to get: a + b = b.

$\red\longrightarrow$ Since a = b (that's the assumption we started with), we can substitute b in for a to get: b + b = b.

$\red\longrightarrow$ Combining the two terms on the left gives us: 2b = b

$\red\longrightarrow$Since b appears on both sides, we can divide through by b to get: 2 = 1

And therefore, we proved 1=2 using a&b method.

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Answer 2

$\huge\green{αղร աҽɾ}$

⟶ Assume that we have two variables a and b, and that: a = b.

⟶ Multiply both sides by a to get: a^2² = ab.

⟶ Subtract b^2² from both sides to get: a^2² - b^2²= ab - b^2²

⟶ (a + b)(a - b) = b(a - b)

⟶ Since (a - b) appears on both sides, we can cancel it to get: a + b = b.

⟶ Since a = b (that's the assumption we started with), we can substitute b in for a to get: b + b = b.

⟶ Combining the two terms on the left gives us: 2b = b

⟶ Since b appears on both sides, we can divide through by b to get: 2 = 1

And therefore, we proved 1=2 using a&b method.

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