Prove that 1-2sin theta cos theta the whole square = sin theta cos theta
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Step-by-step explanation:
ANSWER
LHS=(1−sinθ+cosθ)
2
LHS=1+sin
2
θ+cos
2
θ−2sinθ+2cosθ−2sinθcosθ
LHS=2−2sinθ+2cosθ−2sinθcosθ
LHS=2(1−sinθ)+2cosθ(1−sinθ)
LHS=2(1−sinθ)(1+cosθ)=RHS
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