prove that 1+2sinA-2cosA/1+2sinA + 2cosA
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We know the formula,
sin A = 1-2cosA
so,
sin²A = 1-4cosA+4cos²A
1-cos²A = 1-4cosA+4cos²A
0 = 5cos²A-4cosA
0 = cosA(5cosA-4)
cosA=0 or cosA=4/5
If cosA=0 then one possibility is sinA=1 and in this case 2sinA-cosA=2.
At first I thought cosA=0 and sinA=-1 was possible but this is not consistent with sinA+2cosA=1.
Let's consider the case cosA=4/5.
Then sinA = ±√(1-cos²A) = ±√(1-16/25) = ±3/5
If cosA=4/5 and sinA=3/5 then sinA + 2cosA doesn't equal 1.
If cosA=4/5 and sinA=-3/5 then sinA + 2cosA does equal 1 but 2sinA-cosA= -2.
So my conclusion is that if sinA+2cosA=1 then 2sinA-cosA can equal either 2 or -2.
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