Question

Prove that (1 ,7)(4,2)(-1,-1)(-4,4) are the Vertices of a square​

Answer 1

Answer:

Given points are (1,7),(4,2),(-1,-1),(-4,4)

Let the points are A,B,C,D.

Distance formula = √(x₂-x₁)²+(y₂-y₁)²

                    AB = √(4-1)²+(2-7)²

                          = √9+25

                          = √34

                     BC = √(-1-4)²+(-1-2)²

                           = √25+9

                           =  √34

                      CD = √(-4-(-1))²+(4-(-1))²

                            = √9+25

                            =  √34

                       DA = √(1-(-4))²+(7-4)²

                             = √25+9

                             = √34

Answer 2

Answer:

Hi mate heres your answer.

Step-by-step explanation:

Let the points be A,B,C,D

Distance formula = (√x2-x1 + √y2-y1)^2

AB = √34, BC = √34, CD = √34, DA = √34

So It is a square.

Hope you get it.

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