Prove that 1-√7 is an irrational number
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Answered by
12
howdy!!
your answer is ----
Let, us assume that 1-√7 is rational
so, 1-√7 = a/b where , a and b are integers and b is not equal to zero
=> b-a/b = √7
since , b-a/b is a rational because a and b are integers and b is not equal to zero
so, √7 is also a rational
[ since √7 = b-a/b ]
but this contradict the fact that √7 is irrational
therefore , our assumption is wrong
hence , 1-√7 is irrational .
hope it help you ✌✌✌✌✌✌✌✌✌
your answer is ----
Let, us assume that 1-√7 is rational
so, 1-√7 = a/b where , a and b are integers and b is not equal to zero
=> b-a/b = √7
since , b-a/b is a rational because a and b are integers and b is not equal to zero
so, √7 is also a rational
[ since √7 = b-a/b ]
but this contradict the fact that √7 is irrational
therefore , our assumption is wrong
hence , 1-√7 is irrational .
hope it help you ✌✌✌✌✌✌✌✌✌
Answered by
1
Answer:
1-root 7
Step-by-step explanation:
Go check it your self in Google the answer is wrong
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