prove that 1/a + 1/b= 1/c if pq is perpendicular qs, tu is perpendicular qs and rs is perpendicular
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Answer:
We have, c=75
∘
∴a=
5
2
c=
5
2
×75
∘
=30
∘
Now, UT∥PQ
⇒c=a+b (Alternate angles)
⇒75
∘
=30
∘
+b⇒b=75
∘
−30
∘
=45
∘
Also, PQ∥RS
∴b+d=180
∘
(Co-interior angles)
⇒d=180
∘
−45
∘
=135
∘
So, b+
2
d
=45
∘
+
2
135
∘
=45
∘
+67.5
∘
=112.5
∘
Step-by-step explanation:
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