Question

prove that 1 by 3 root 2 is an irrationalnumber

Answer 1

let us assume 1by 3root2 is rational
let us multiply root 2 up and down
so root2 by6 =a/b ( a and b are integers and b is not equal to 0 )
root 2 = a*6b
=integer*6/integer
=rational

but this contradicts with the fact that 3 √2 is irrational., therefore, our assumption is wrong
1/3√2 is irrational.

:)