prove that 1 by 3 root 2 is irrational
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Let us assume that 1 /3√2 is rational
any rational no. can be written in the form of a/b
1 /3√2=a/b (a &b are integers and b#0)
by cross multiplication we get
b/3a=√2
that means
√2=b/3a
but this is a contradiction because (√2 is irrational we have proved in earlier classes)and b/3a=rational ,b&3a both are integers)
therefore our assumption is wrong because √2(irrational)≠b/3a(rational)
hence 1by3root2 is irrational
any rational no. can be written in the form of a/b
1 /3√2=a/b (a &b are integers and b#0)
by cross multiplication we get
b/3a=√2
that means
√2=b/3a
but this is a contradiction because (√2 is irrational we have proved in earlier classes)and b/3a=rational ,b&3a both are integers)
therefore our assumption is wrong because √2(irrational)≠b/3a(rational)
hence 1by3root2 is irrational
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