Question

prove that 1 – cos^2Ѳ – sin^2 Ѳ = 0

Answer 1

Answer:

☆☆☆ SOLUTION ☆☆☆ :–

TO PROVE :‐

$1 - {cos}^{2} \alpha - {sin}^{2} \alpha = 0$

L.H.S. :–

$= 1 - { \cos }^{2} \alpha - {sin}^{2} \alpha \\ \\ = 1 - ( {cos}^{2} \alpha + {sin}^{2} \alpha ) \\ \\ = 1 - 1 \\ \\ = 0$

= R.H.S

♧♧♧ HENCE PROVED ♧♧♧

#FOLLOW ME.....

Answer 2

ANSWER

FORMULA USED

SIN^2X+COS^2X = 1

PROOF

LHS

= 1-SIN^2X-COS^2X

= 1- (SIN^2X+COS^2X)

= 1 - 1

= 0

HP

proof of SIN^2X+COS^2X = 1 is in ncert class 11

here not required if you have to know see there

hope it helps

follow me

bye