Question

Prove that 1+cos theta by 1-cis theta=(cosec theta+cot theta)​

Answer 1

Answer:

Step-by-step explanation:

(cosecA-cotA)^2=1-cosA÷1+cosA

(1/sinA-cosA/sinA)^2

(1-cosA÷sinA)^2

(1-cosA)^2÷sin^2A

(1-cosA)(1-cosA)÷1-cos^2A

(1-cosA)(1-cosA)÷(1-cosA)(1+cosA)

(1-cosA)÷(1+cosA)

Hence, proved