Question

prove that 1+cos0÷sinO÷ 1+ cos 0 = sin theta + cos theta.
​

Answer 1

Step-by-step explanation:

LHS = sine 1 + cos 0 1 + cos 0 sin 0 +

LHS sin² 0 + (1 + cos 0)² sin 0(1+cos 0) =

sin² 0 + 1 + 2 cos 0 + cos² 0 sin 0(1+ cos 0) → LHS =

→ LHS = (sin² 0 + cos²0) + 1 + 2 cos 0 sin 0(1+ cos 0)

[ sin²+ cos² 0 = 1]

2 + 2 cos 0 sin 0(1+ cos 0) → LHS

2(1 + cos 0) sin 0(1 + cos 0) 2 sin Ꮎ = 2 cosec 0 RHS =