prove that (1 - cos²A) cosec²A =
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The following is a trigonometric identity:
sec2A−sin2Atan2A=csc2A−cos2A
Rewrite the left-hand side entirely in terms of sin and cos , obtaining:
sec2A−sin2Atan2A=1cos2A−sin2Asin2Acos2A
Now, multiply the top and bottom by cos2A:
1cos2A−sin2Asin2Acos2A=1−sin2Acos2Asin2A
Then, split up the fraction into two terms:
1−sin2Acos2Asin2A=1sin2A−sin2Acos2Asin2A=1sin2A−cos2A
Finally, use the definition of csc to obtain the identity:
sec2A−sin2Atan2A=csc2A−cos2A
I hope you are understand my solution
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