Question

prove that
:- (1 - cos²A) sec² B + tan² B (1 - sin² A) = sin² A + tan²B​

Answer 1

Step-by-step explanation:

plz see image Answer is solved ❤

Answer 2

Step-by-step explanation:

(1 - cos²A) sec²B + tan²B (1-sin²A) = sin²A + tan²B

• 1 - cos²A = sin²A

sin²A sec²B + tan²B - tan²A sin²A = sin²A + tan²B

sin²A ( sec²B - tan²A ) + tan²B = sin²A + tan²B

• sec²B - tan²A = 1

sin²A + tan²B = sin²A + tan²B