prove that (1- cos2A +sin2A )÷ (1+cos2A +sin2A) = tanA
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Answer:
Step-by-step explanation:
1-cos2A+sin2A/1+cos2A+sin2A
=1-(1-2sin^2A)+2sinAcosA/1+2cos^2A-1+2cosAsinA
=1-1+2sin^2A+2sinAcosA/1-1+2cos^2A+2sinAcosA
=2sin^2A+2sinAcosA/2cos^2A+ 2sinAcosA
=2sinA(sinA+cosA)/2cosA(cosA+sinA)
=sinA/cosA
=tanA
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