prove that
1-cos2tita/
sin 2tita=
tantita
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Answer:
(1-cos2θ)/(sin2θ)=tanθ
(1-[cos2θ - sin2θ])/(2sinθcosθ) = tanθ
(1-cos2θ+sin2θ)/(2sinθcosθ) = tanθ
(sin2θ+sin2θ)/(2sinθcosθ) = tanθ
(2sin2θ)/(2sinθcosθ) = tanθ
sinθ/cosθ = tanθ
tanθ = tanθ
Step-by-step explanation:
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