prove that 1+COS2x + COS4x + Cos6x = 4 cosx COS2x cos 3x
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Answer:
⇒(1+cos2x)+(cos6x+cos4x)−4cosxcos2xcos3x
⇒2cos
2
x+2cos5xcosx−4cosxcos2xcos3x
=2cosx[cos5x+cosx]−4cosxcos2xcos3x
=2cosx(2cos3xcos2x)−4cosxcos2xcos3x
=4cosxcos2xcos3x−4cos4xcos2xcos3x
=0
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