Question

prove that:-
√1+cosA÷ 1+cosA + √1- cosA÷ 1+cosA= 2 cosecA ( it is whole root over in LHS but separately).​

Answer 1

Answer :  LHS=RHS

1-cosA=2sin²(½A)

1+cosA≈2cos²(½A)

Hence,

LHS=√｛sin²(½A)/cos²(½A)｝=tan(½A)

RHS=(1/s)-(c/s)≈(1-c)/s=2sin²(½A)/2sin(½A)cos(½A)=sin(½A)cos(½A)

=tan(½A)

∴LHS=RHS

Step-by-step explanation: