Question

prove that ........1-cosA/1+cosA=(cotA-cosecA)^2​
plzzz fast replyyyyy...

Answer 1

Answer:

Step-by-step explanation:

$\frac{1-cosA}{1+cosA}$

take the conjugate of the denominator and multiply it to the  numerator and  denominator

$\frac{(1-cosA)(1-cosA)}{(1+cosA)(1-cosA)}$

$\frac{(1-cosA)^{2} }{1^{2}-cos^{2} A }$

$\frac{1^{2}-2cosA+cos^{2}A }{sin^{2}A }$

$\frac{1^{2} }{sin^{2} A} -\frac{2cosA}{sin^{2}A } +\frac{cos^{2}A }{sin^{2}A }$

$(\frac{1}{sinA}-\frac{cosA}{sinA} ) ^{2}$

$(cosecA-cotA)^{2}$

I guess there is a mistake in the question.....not sure