Question

prove that 1-cosA+sinA÷sinA+cosA-1=1+sinA/CosA​

Answer 1

Step-by-step explanation:

Here is the solution -

=(sinA + 1 - cosA) / (cosA - 1 + sinA)

Divide each term by cosA

=(tanA + secA - 1) / (1 - secA + tanA)

=[tanA + secA - ( sec2A−tan2A )] /

( 1 - secA + tanA)

= (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)

= tanA + secA

= (sinA / cosA )+ 1 / cosA

= (sinA + 1 )/ cosA

Hence Proved

Hope it will help you