Question

prove that 1/(cosec theta - cot theta) - 1/sin theta = 1/sin theta -1/(cosec theta + cot theta)

please help ​

Answer 1

Trigonometry

LHS = {1/( cosecA - cotA)} -1/sin A

= {(cosec²A-cot²A)/(cosecA-cotA)} - 1/sinA

= (cosecA + cotA) - cosecA

= cosecA - ( cotA - cosecA)

= (1/sinA) - {( cotA - cosecA)/(cosec²A - cot²A)}

= (1/sinA) - 1/(cosecA + cotA)

That's it

Hope it helped

(O_o)

Answer 2

Answer:

Hiiiiii doing aa you said.