prove that 1+cosx/1-cos x= tan^2 x /(sec x -1)^2
Answers
Answered by
2
Answer:
Step-by-step explanation:
Lets take the RHS
tan^2x/[secx-1]^2
=sec^2x-1/[secx-1]^2
{tan^2x=sec^2x-1}
=[secx+1][secx-1]/[secx-1][secx-1]
=[secx+1]/[secx-1]
=[1/cosx]+1 divided by [1/cosx]-1
=[1+cosx]/cosx whole divided by [1-cosx]/cosx
=1+cosx/1-cosx
LHS=RHS
Similar questions