Question

Prove that: (1 + cot 0 + cosec 0) (1 + cot 0 - cosec 0) = 2 cot 0​

Answer 1

Answer:

(1+ cot0 + cosec0) (1 + cot0 - cosec0) = 2 cot0

L.H.S

= [ (1+cot0) + (cosec0)] [(1+cot0) - (cosec0)]

= (1 +cot0)Sq - (cosec0)Sq

= 1 + cotSq + 2cot0 - cosecSq

= 2cot0 + 1 +[ cotSq - cosecSq]

= 2cot0 + 1 - 1 [cotSq +1 = cosecSq]

= 2cot0

PROVED