Question

prove that 1+(cot^2 /1 + cosec theta) = 1/sin theta

Answer 1

♧♧HERE IS YOUR ANSWER♧♧

Trigonometry is the study of angles and its ratios. This study prescribes the relation amongst the sides of a triangle and angles of the triangle.

There are sine, cosine, tangent, cot, sectant and cosec ratios to an angle of a triangle.

Let me tell you an interesting fact about Trigonometry.

"Triangle" > "Trigonometry"

Remember some formulae now :

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

cosec²θ - cot²θ = 1

Want to learn more!

Here it is :

sin(A + B) = sinA cosB + cosA sinB

sin(A - B) = sinA cosB - cosA sinB

cos(A + B) = cosA cosB - sinA sinB

cos(A - B) = cosA cosB + sinA sinB

(SEE THE ATTACHMENT)

♧♧HOPE THIS HELPS YOU♧♧

Answer 2

Heya....❤

ur answer is

1+(cot^2/1+cosec)=1/sin

cosec^2+cosec/1+cosec

cosec(cosec+1)/cosec+1

cosec

1/sin

Hence proved

LHS=RHS