prove that 1+(cot^(2)alpha)/(1+cosec alpha)]^2-cot2alfpha =1
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Answer:
LHS =1+
(1+cosecα)
cot
2
α
=1+
(1+cosecα)
(cosec
2
α−1)
[∵cot
2
α=cosec
2
α−1]
=1+
(cosecα+1)
(cosecα−1)(cosecα+1)
[∵a
2
−n
2
=(a−b)(a+b)]
=cosecα
Hence proved .
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