Question

Prove that (1+ cot e-cosec
0
) + (1 + tan 0 + sec 0 ) = 2.​

Answer 1

Answer:

LHS =1+cotA−cosecA=1+

sinA

cosA

−

sinA

1

=

sinA

(sinA+cosA−1)

1+tanA+secA=1+

cosA

sinA

+

cosA

1

=

cosA

(sinA+cosA+1)

(1+cotA−cosecA)(1+tanA+secA)

=

sinAcosA

(sinA+cosA−1)(sinA+cosA+1)

=

sinAcosA

(sinA+cosA)

2

−1

=

sinAcosA

1+2sinAcosA−1

=2=RHS

Hence Proved