Prove that (1 + cot teta - cosec teta )(1 + tan teta + sec teta) = 2.
Answers
Answered by
2
Answer:
2. Ans.
Step-by-step explanation:
->LHS= [1+cos/sin-1/sin][1+1/cos+sin/cos]
= [cos+sin-1][cos+sin+1]/cos*sin
=[cos+sin]^2-(1)^2/cos*sin
=1+2cos•sin-1/cos•sin
now 1 and -1 will be cut down
=2cos•sin/cos•sin
cos•sin will cut down
= 2 ....Ans.
HOPE THIS WILL HELP YOU!
Answered by
6
To Prove :
- (1 + cot theta - cosec theta )(1 + tan theta + sec theta) = 2.
Solution :
LHS :(1 + cotØ - cosecØ)(1 + tanØ + secØ)
we know that,
- cotØ = cosØ/sinØ
- tanØ = sinØ/cosØ
- cosecØ = 1/sinØ
- secØ = 1/cosØ
we know that,
- sin²Ø + cos²Ø = 1
= 2
Hence, Proved
━━━━━━━━━━━━━━━━━━━━━━━━━
Similar questions