prove that (1+cot theta+tan theta)(sin theta- cos theta)/sec³ theta -cosec³ theta= sin² theta cos²theta
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1+cos
2
θcsc
2
θ
1+sin
2
θ⋅sec
2
θ
=tanθ
1+
sin
2
θ
cos
2
θ
1+
cos
2
θ
sin
2
θ
1+cot
2
θ
1+tan
2
θ
csc
2
θ
sec
2
θ
cos
2
θ
sin
2
θ
tan
2
θ
=tanθ
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