Question

Prove that 1+cot2 theta/1+cosec theta = 1/sin theta

Answer 1

LHS.

$\frac {1 + cot^2A} { 1 + cosecA} \\ \\= \frac{cosec^2A} {cosec^A} \: \: \: \: [using \: \:identity] \\ \\ = \frac{cosecA * cosecA} { cosecA} \\ \\ = cosecA \\ \\ = \frac {1}{sin A} = RHS \\ \\ Hence \: Proved.$

Answer 2

Answer:

see this method is called chomu method. Discovered by dinu .in 1908 april 5 at 10 o clock

Step-by-step explanation:

So equating LHS,

(1+Cot2 theta/1+cosec theta)*0=0

so equating RHS,

(1/sin theta)*0

LHS=RHS

0=0

THEREFORE PROVED BY CHOMU METHOD...

if teacher aint give any marks write ask dinu