Question

prove that: (1+CotA)(1-CosA)(1+Cot²A)=1​

Answer 1

Answer:

Prove that (1-cosA)(1+cosA)(1+cotA×cotA)=1 ... ( 1 + CotA × Cot ) => ( 1 - Cos²A ) ( 1 + Cot²A ) => Sin²A × Cosec²A => Sin²A × 1/ Sin²A => 1

Answer 2

Answer:

◾( 1 - CosA ) ( 1 + CosA) ( 1 + CotA × CotA) = 1

Now , using the identity ( a - b ) (a + b ) = ( a² - b² )

=>> ( 1 - Cos²A ) ( 1 + Cot²A)

=>> Now,

========

◀1 - Cos² A = Sin²A as

◀1 + Cot²A = Cosec²A

〰▪Putting in Values ,

( Sin²A ) ( Cosec²A)

=>>> Now, Sin²A = 1/ Cosec²A

We have !!

--------------

( Sin²A ) × 1/ Sin²A

= 1 = RHS!!

Please mark me brainliest