Prove that (1+cotA+t
anA) (sinA-cosA)= sinA tanA-cotA×cosA
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Answer:
L.H.S = (1+cotA+tanA)(sinA-cosA)
= (sinA+sinAcotA +tanAsinA-cosA -cosAcotA -tanAcosA)
=(sinA+sinAcosA/sinA+tanAsinA-cosA-cosAcotA -cosAsinA/cosA)
= (sinA+cosA+tanAsinA -cosA- cosAcotA -sinA)
= tanAsinA -cosAcotA
= sinAtanA-cotAcosA
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