prove that 1/(cotA+tanA)=sinAcosA
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LHS=SinAcosA(sinA/cosA+cosA/sinA)
SinAcosA(sin2A+cos2A/sinAcosA)
Sin2A+cos2A
1
RHS=1
Therefore,LHS=RHS.
Hopefully this helps you
SinAcosA(sin2A+cos2A/sinAcosA)
Sin2A+cos2A
1
RHS=1
Therefore,LHS=RHS.
Hopefully this helps you
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