prove that: 1/cottheta-cot3theta + 1/tan3theta-tantheta
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Answer:
We have
cotθ−cot3θ
cotθ
+
tanθ−tan3θ
tanθ
=
sinθ
cosθ
−
sin3θ
cos3θ
sinθ
cosθ
+
cosθ
sinθ
−
cos3θ
sin3θ
cosθ
sinθ
=
sinθsin3θ
cosθsin3θ−cos3θsinθ
sinθ
cosθ
+
cosθcos3θ
sinθcos3θ−sin3θcosθ
cosθ
sinθ
=
cosθsin3θ−cos3θsinθ
cosθsin3θ
+
sinθcos3θ−sin3θcosθ
sinθcos3θ
=
cosθsin3θ−cos3θsinθ
cosθsin3θ
−
sin3θcosθ−sinθcos3θ
sinθcos3θ
=
cosθsin3θ−cos3θsinθ
cosθsin3θ−sinθcos3θ
=1
Step-by-step explanation:
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