Question

PROVE That 1+∆=E


please help​

Answer 1

Answer:

Following results show the similarity of factorial notation and differential operator. Property 3.1 ∆x(n) = nhx(n-1). Proof. ∆x(n) ...

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Answer 2

Answer:

Δ =E-1

1+Δ =E

Step-by-step explanation:

The relation between shifting operator and forward operator

Δ= Forward difference operator

E=shifting operator

E f(x)=f(x+h)    ==>1

Δ f(x)=f(x+h)-f(x)==>2

Δ f(x)=f(x+h)-f(x)

Substitute equation 1 in equation 2

Δ f(x)=E f(x)-f(x)

Taking  f(x)  common

Δ f(x)= f(x)(E-1)

cancel f(x)

Δ =E-1

We can rewrite as

1+Δ =E

Hence proves