Prove that [ -1+i√3/2 ]² is a positive integer
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Step-by-step explanation:
(4x^2 + 12x + 9)
√(2x+3)^2
= 2x+3
Answer says its |2x+3|
Shouldn't the square cancel out the square root such as
√9 = √(3)^2 = 3 obviously its not |3|
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