prove that (1 + i)^4 ×[ 1+1/i ]^4 =16
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Answer:
At first apply the formula on LHS ,
[(a+b)²] = (a² + 2ab + b²)
then solve it and put the value of i² = -1.
(1 + i) ² (1+1/i)² = 16
LHS : =(1+i)² (1+1/2)²
= (1 + 2i +i²)² (1+2/i +1/i²)²
=(1+ 2i-1)² [1+(2/i )-1]² { i²= -1
=(2i)² (2i)²
=(-4) (-4)
= 16
RHS :
16
Hence, LHS = RHS
Read more on Brainly.in - https://brainly.in/question/11936243#readmore
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