prove that (1+i)^4 ×(1+1/i)^4=16
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1
Answer:
-14
Step-by-step explanation:
1+I*4times*1+1/I*4times=16
1+i*1+i*1+i*1+i *1+1/i*1+1/i*1+1/i*1+1/i=16
1+4i *(1+1/4i)=16
1+4i*1/4i+1=16
1+1*4i*1/4i=16
2*(4i*1/4i)=16
2*1=16
2=16
2-16=0
0=-14
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