Question

prove that 1+i²+i⁴+i⁶=0​

Answer 1

Solution:

$= 1 + {i}^{2} + {i}^{4} + {i}^{6} \\ \\ = 1 + (- 1) + (1) + (i) {}^{2} . {i}^{4} \\ \\ = 1 - 1 + 1 - 1 \\ \\ = 0$