Prove that :
1)if the potential difference gets doubled , the current flowing through it also gets doubled.
2) if the potential difference is halved,the current flowing through it also gets halved .
3) if resistance is doubled , the current gets halved .
4) if resistance is halved , the current gets doubled.
please answer in brief , I need proof not statement
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Answered by
5
Answer:
According to V = IR.
Rearranging,
➸ I = V/R.
1) The potential difference is doubled.
➸ I = 2V/R
➸ I = 2*V/R
➸ New current = 2*I
Current gets doubled.
2) The potential difference is halved.
➸ I = ½*V/R
➸ I = V/2R
➸ New current = I/2
Current gets halved.
3) If resistance is doubled.
➸ I = V/2R
➸ I = ½*V/R
➸ New current = I/2
Current gets halved.
4) If resistance is halved.
➸ I = V/½R
➸ I = V/(R/2)
➸ I = V*2/R
➸ I = 2V/R
➸ New current = 2I
Current gets doubled.
Answered by
0
Answer:
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