Prove that 1 joule = 10⁷ erg.
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Answer:
1 joule = 1 kg m^2/s^2
1 erg = 1 g cm^2/s^2
n1u1 = n2u2
so, 1 kg m^2/s^2 = n2 g cm^2/s^2
that is, 1×1000×100×100 g cm^2/s^2 = n2 g cm^2/s^2
that is, n2 = 10^7
hence, 1 joule = 10^7 erg
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