Question

Prove that 1
log6 24
+
1
log12 24
+
1 log8 24
= 2​

Answer 1

1/log_6(24) = log_24(6) and so on

1/log_6(24) = log_24(6) and so onSo the relation becomes log_24 (6)+log_24(8)+log_24 (12)

1/log_6(24) = log_24(6) and so onSo the relation becomes log_24 (6)+log_24(8)+log_24 (12)= log_24 (6*8*12) = log_24 ( 24*24) = 2