Question

Prove That
1/loga(abc)+1/logb(abc) +1/logc(abc) =1​​

Answer 1

Answer:

1/loga(abc)+1/logb(abc) +1/logc(abc) =1​​

Step-by-step explanation:

$logx(y) = 1/logy(x)$

using this property

$=1/loga(abc)+1/logb(abc) +1/logc(abc)\\=logabc(a)+logabc(b) +logabc(c)\\=logabc(abc) \\=1$