prove that; 1 .p=d g h 2 .V=u+at please answer
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(1)Let's finding the force at the bottom of the container.
Let,
mass of the container = m
Volume of the container = V
density of the container = d
Area of the bottom = A
Height of the container = h
F = mg
Now,
Pressure = Force / Area
P = F/A
P = m g / A
dividing h on denometer and numerator,
P = mgh / Ah
P = mgh / V ( V = Ah )
P = d g h ( d = m/V)
(2) I will provide you with two types of proofs. Among these two I like logical the most…
Let us begin with Mathematical proof which is that we know that acceleration of a body is change in velocity (v-u) per unit time. Mathematically it is:
a=(v−u)/t
Multiplying t on both sides we get:
at=(v−u)
Adding u on both sides we get:
at+u=(v−u)+u
at+u=v
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