Question

prove that (1/r-1/r1) (1/r-1/r2) (1/r-1/r3)=abc/∆^3=4r/r^2s^2
​

Answer 1

Answer:

Answer

To prove:

r

1

1

+

r

2

1

+

r

3

1

=

r

1

⇒

r

1

1

+

r

2

1

+

r

3

1

=

S

s−a

+

S

s−b

+

S

s−c

=

S

3s−(a+b+c)

We know, s=

2

a+b+c

⇒a+b+c=2s

⇒

r

1

1

+

r

2

1

+

r

3

1

=

S

3r−2r

=

S

r

=

r

1

=

Step-by-step explanation:

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