prove that 1/root 2 is irr rational
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Explanation:
We will prove it by the method of contradiction.
Let 1/√2 is a rational number
So we can write 1/√2 = a/b .........1
where a and b are relatively prime numbers.
Squaring equation 1 on both sides,
(1/√2)^2 = (a/b)^2
=> 1/2 = a^2 /b^2
=> 2a^2 = b^2
So b^2 is an even number
=> b must be an even number
Let b = 2c
On squaring both sides,
=> b^2 = (2c)^2
=> b^2 = 4c^2
now from equation 1
2a^2 = 4c^2
=> a^2 = 2c^2
=> a must be an even number.
Now since both a and b are even numbers, then a and b can not be relatively prime.
So our assumption is wrong.
Hence, 1/√2 is an irrational number.
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