prove that 1+sec a/cosa =sin^2a/1-cos a
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Answer:
To prove :
secA
1+secA
=
1−cosA
sec
12
A
LHS
secA
1+secA
=
cosA
1
1+
cosA
1
=
cosA
1
cosA
cosA+1
=
cosA
cosA+1
×
1
cosA
=1+cosA
=1+cosA×
1−cosA
1−cosA
=
1−cosA
(1)
2
−(cosA)
2
=
1−cosA
1−cos
2
A
=
1−cosA
sin
2
A
=RHS
Step-by-step explanation:
Attachments:
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